Jawaban:

AO = EO = 3

a. panjang OB

OB = √(6² + 3²)

OB = √(36 + 9)

OB = √45

OB = √9 x √5

OB = 3√5

b. panjang OC

cari dulu panjang AC

AC = √(6² + 6²)

AC = √72

AC = √36 x √2

AC = 6√2

kemudian bari cari panjang OC

OC = √(AO² + AC²)

OC = √[3² + (6√2)²

OC = √(9 + 72)

OC = √81

OC = 9

c. ∠ BOC

Δ BOC siku² di B

sin∠BOC = BC/OC

sin∠BOC = 6/9

sin∠BOC = 0,666

∠BOC = 41,75°

d. ∠FOH

pada Δ FOH

ketiga sisinya

FO = OH = FH = diagonal bidang

jadi ketiga sudut FOH sama besar

∠ FOH = 180°/3

∠FOH = 60°

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