Jawaban:

Nomor 1

\begin{gathered}massa\ C=\dfrac{12}{44}\times2,2=0,6\ gram\\\\massa\ H=\dfrac{2}{18}\times1,8=0,2\ gram\\\\C:H=\dfrac{0,6}{12}:\dfrac{0,2}{1}=1:4\\\\Jadi\ rumus\ empiris\ senyawa\ adalah\ \boxed{\bold{CH_4}}\end{gathered}

massa C=

44

12

×2,2=0,6 gram

massa H=

18

2

×1,8=0,2 gram

C:H=

12

0,6

:

1

0,2

=1:4

Jadi rumus empiris senyawa adalah

CH

4

Nomor 2

\begin{gathered}massa\ C=\dfrac{12}{44}\times4,4=1,2\ gram\\\\massa\ H=\dfrac{2}{18}\times2,7=0,3\ gram\\\\C:H=\dfrac{1,2}{12}:\dfrac{0,3}{1}=1:3\\\\Rumus\ empiris:\ CH_3\\\\V_m=\dfrac{30}{7,5}\times5=20\ L/mol\\\\Mr=\dfrac{20}{1}\times1,5=30\\\\Mr(CH_3)_x=15x=30\rightarrow x=2\\\\Jadi\ rumus\ molekul\ senyawa\ \boxed{\boxed{\bold{C_2H_6}}}\end{gathered}

massa C=

44

12

×4,4=1,2 gram

massa H=

18

2

×2,7=0,3 gram

C:H=

12

1,2

:

1

0,3

=1:3

Rumus empiris: CH

3

V

m

=

7,5

30

×5=20 L/mol

Mr=

1

20

×1,5=30

Mr(CH

3

)

x

=15x=30→x=2

Jadi rumus molekul senyawa

C

2

H

6

Penjelasan:

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