Jawaban:

3a. 7.2 L

b. 2.8 L

Penjelasan:

semua reaksi hrs disetarakan dahulu & dicari molnya

mol Al = gr/Ar = 5.4/27 = 0.2 mol

mol H2O4 = Molar × Vol = 1 × 1 = 1 mol

dicari pereaksi pembatasnya krn diketahui mol ke2 pereaksinya, caranya:

0.2 mol Al ÷ koefisien Al = 0.2/2 = 0.1

1 mol H2SO4 ÷ koefisien = 1/3 = 0.33

krn 0.1 < 0.33 jadi Al sbg pereaksi pembatasnya (tdk ada sisa di akhir reaksi)

3a.

25⁰C, 1 atm (RTP= Room Temperature Pressure) jd cari vol caranya = mol gas × 24

Vol H2 = 0.3 × 24 = 7.2 Liter

3b.

kelebihan asam sulfat di akhir reaksi = 0.7 mol

H2SO4 + 2 NaOH --> Na2SO4 + 2 H2O

0.7 mol ~ 2(0.7)

cara cari mol NaOH = mol H2O4 dikali 2 (krn koefisien NaOH = 2 × lipatnya) = 2 (0.7) = 1.4 mol

M NaOH = mol/vol

0.5 = 1.4/vol

vol NaOH = 2.8 Liter